SOLUTION: A city is growing at the rate of 0.7% annually. If there were 4,913,000 residents in the ciyt in 1972, find how many(to the nearest ten-thousand) are living in the city in 2000.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: A city is growing at the rate of 0.7% annually. If there were 4,913,000 residents in the ciyt in 1972, find how many(to the nearest ten-thousand) are living in the city in 2000.      Log On


   

Question 271286: A city is growing at the rate of 0.7% annually. If there were 4,913,000 residents in the ciyt in 1972, find how many(to the nearest ten-thousand) are living in the city in 2000.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
4,913,000(1+.007)^28
4,913,000*1.007^28
4,913,000*1.2157
5,970,000 POPULATION IN 2000