SOLUTION: One half of a certain even integer plus one fifth of the next consecutive even integer equals 48. Find the two integers.

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: One half of a certain even integer plus one fifth of the next consecutive even integer equals 48. Find the two integers.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 271182: One half of a certain even integer plus one fifth of the next consecutive even integer equals 48. Find the two integers.
Found 3 solutions by stanbon, craigt, richwmiller:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
One half of a certain even integer plus one fifth of the next consecutive even integer equals 48. Find the two integers.
---
1st even: 2x
2nd even: 2x+2
----------------------
Equations:
(1/2)(2x) + (1/5)(2x+2) = 48
Multiply thru by 10 to get:
10x + 2(2x+2) = 480
14x + 4 = 480
14x = 476
x = 34
-----
1st = 2x = 68
2nd = 2x+2 = 70
=====================
Cheers,
Stan H.

Answer by craigt(10) About Me  (Show Source):
You can put this solution on YOUR website!
Two integers are x and x+2
%281%2F2%29%28x%29%2B%281%2F5%29%28x%2B2%29=48 Multiply both sides by 10 to eliminate fractions:
5x%2B2%28x%2B2%29=480
7x%2B4=480
x=68 and x%2B2=70
68 & 70

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
n/2+(n+2)/5=48
5n+2n+4=480
7n=476
n=68
n+2=70
check
34+14=48
48=48
ok