SOLUTION: Please help me solve this equation: {{{(3a-5)/(a^2+4a+3)+(2a+2)/(a+3)=(a-3)/(a+1)}}} Here's what I have tried: {{{(3a-5)/((a+3)(a+1))+(2(a+1))/(a+3)=(a-3)/(a+1)}}} LCM: (a+3)(a

Algebra ->  Rational-functions -> SOLUTION: Please help me solve this equation: {{{(3a-5)/(a^2+4a+3)+(2a+2)/(a+3)=(a-3)/(a+1)}}} Here's what I have tried: {{{(3a-5)/((a+3)(a+1))+(2(a+1))/(a+3)=(a-3)/(a+1)}}} LCM: (a+3)(a      Log On


   

Question 271150: Please help me solve this equation: %283a-5%29%2F%28a%5E2%2B4a%2B3%29%2B%282a%2B2%29%2F%28a%2B3%29=%28a-3%29%2F%28a%2B1%29
Here's what I have tried:
LCM: (a+3)(a+1)
%283a-5%29%2F%28a%2B3%29%28a%2B1%29%D7%28a%2B3%29%28a%2B1%29=3a-5
%282%28a%2B1%29%29%2F%28a%2B3%29%D7%28a%2B3%29%28a%2B1%29=2%28a%2B1%29%5E2
%28a-3%29%2F%28a%2B1%29%D7%28a%2B3%29%28a%2B1%29=%28a-3%29%28a%2B3%29=a%5E2-9
3a-5%2B2%28a%5E2%2B2a%2B1%29=a%5E2-9
3a-5%2B2a%5E2%2B4a%2B2=a%5E2-9
2a%5E2%2B7a-3=a%5E2-9
2a%5E2-a%5E2%2B7a-3=a%5E2-a%5E2-9
a%5E2%2B7a%2B3=-9
a%5E2%2B7a%2B3-3=-9-3
a%5E2%2B7a=-12
and then I got stuck. Did I do something wrong somewhere? I see that I can factor out a on the left side, but I'm supposed to be solving for a. So if I factor out a I'm still left with a(a+7) and to solve for a I would have to divide by 7? Don't I have to divide All terms on the left by 7 then? Maybe I'm just getting too tired but I really don't know what to do next. I would really appreciate a nudge in the right direction. I forgot to say thank you in advance on my last question, so Thanks in advance on this one and the last one.
~Kendra~
Answer by Greenfinch(383) About Me  (Show Source):
You can put this solution on YOUR website!
Minor sign problem I think.
a^2 + 7a -3 = -9 not +3
a^2 + 7a +6 = 0
(a + 6)(a + 1) = 0
a = -6 or -1