SOLUTION: In Paul's bank, there is $2.60 in pennies, nickels, and dimes. In all there are 45 coins. If there are twice as many nickels as pennies, find how many of each kind there are.

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Question 27112: In Paul's bank, there is $2.60 in pennies, nickels, and dimes. In all there are 45 coins. If there are twice as many nickels as pennies, find how many of each kind there are.
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Let the pennies be x
Let the nickels be 2x
Let the dimes be y

so:
x+2x+y=45 comin total solve for y
y=45-3x (subsitution)

Nickels value = 5
Dime value = 10
Pennie value = 1
Total value = 260

5(2x)+10(y)+x=260 (subsitute for y)
10x+10(45-3x)+x=260
10x+450-30x+x=260
-19x=-190
x=10

2(10)=20
y=45-3(10)
y=45-30
y=15

Hence, there were 10 pennies, 20 nickels and 15 dimes.
Paul.