SOLUTION: Please can you solve the following equation for {{{0<x<360}}} {{{sin x cos 150 + cos x sin 150 = 1/2 }}} ? Thank you

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Question 27110: Please can you solve the following equation for 0%3Cx%3C360
sin+x+cos+150+%2B+cos+x+sin+150+=+1%2F2+
?
Thank you

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
sin+x+cos+150+%2B+cos+x+sin+150+=+1%2F2+
sin(x+150)=0.5
sin(90+60+x)=0.5
-cos(60+x)=0.5
cos(60+x)=-0.5
60+x=120 degrees...if you are taught general solutions then 60+x=2n(pi)+-(pi)/3
x=60 degrees....if you are taught general solutions then x=2n(pi)+-(pi)/3-(pi)/3
...........................................x=2n(pi)..or...2n(pi)-2(pi)/3