Question 27070: Judy is 3 times as old as Phyillis. In 10 years, Judy will be twice as old as Phyllis. Find their present age? Answer by Earlsdon(6294) (Show Source):
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Let J = Judy's present age and P = Phyllis's present age.
J = 3P and in 10 year's time:
J+10 = 2(P+10) Substitute the J = 3P from the first equation into the second equation and solve for P.
(3P)+10 = 2(P+10) Simplify.
3P+10 = 2P+20 Subtract 2P from both sides.
P+10 = 20 Subtract 10 from both sides.
P = 10 and
J = 3P = 3(10) = 30
Judy is 30 years old and Phyllis is 10 years old.
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