| 
 
 
| Question 270692:  Jeffrey wrote 1 on 1 slip of paper, 2 on 2 slips of paper, 3 on 3 slips of paper, 4 on 4 slips of paper, 5 on 5 slips of paper and 6 on 6 slips of paper.lf he draws 1 slip of Paper at random, what is Probability of getting an odd number?
 
 A 1/2   b 2/5   c 3/4   d 5/6   e 3/7
 
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Jeffrey wrote 1 on 1 slip of paper, 2 on 2 slips of paper, 3 on 3 slips of paper, 4 on 4 slips of paper, 5 on 5 slips of paper and 6 on 6 slips of paper.lf he draws 1 slip of Paper at random, what is Probability of getting an odd number? ---
 # of ways to succeed: 1+3+5 = 9
 # of possible outcomes: 1+2+3+4+5+6 = 21
 ---
 P(odd) = 9/21 = 3/7
 ===============
 Cheers,
 Stan H.
 A 1/2 b 2/5 c 3/4 d 5/6 e 3/7
 
 | 
  
 | 
 |