SOLUTION: If 6 times a number is decreased by 5, the result is 7 more than the sum of 3 times the number and 13. what is the number?

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Question 270653: If 6 times a number is decreased by 5, the result is 7 more than the sum of 3 times the number and 13. what is the number?
Found 2 solutions by josmiceli, mananth:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let n = the number
given:
6n+-+5+=+3%2A%28n+%2B+13%29+%2B+7
6n+-+5+=+3n+%2B+39+%2B+7
Subtract 3n from both sides
3n+-+5+=+46
3n+=+51
n+=+17
The number is 17

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
If 6 times a number is decreased by 5, the result is 7 more than the sum of 3 times the number and 13. what is the number?

let the number be x
6 times a number is 6x
this is decreased by 5 meaning 6x-5 ( first part of the equation)


number plus 13 is x+13
3times the number plus 13
= 3(x+13)
seven more than 3(x+13)
3(x+13) +7
6x-5 = 3(x+13)+7
6x-5 = 3x +39 +7
6x-3x= 39+7+5
3x= 51
x= 17