SOLUTION: 23-2[4+3(x-1)]+5[x-2(x+3)]=7 {x-2[5-(2x+3)] }
this all looks like jumble to me, my I please get this problem broken down step by step; PLEASE
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: 23-2[4+3(x-1)]+5[x-2(x+3)]=7 {x-2[5-(2x+3)] }
this all looks like jumble to me, my I please get this problem broken down step by step; PLEASE
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Question 270585: 23-2[4+3(x-1)]+5[x-2(x+3)]=7 {x-2[5-(2x+3)] }
this all looks like jumble to me, my I please get this problem broken down step by step; PLEASE Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 23-2[4+3(x-1)]+5[x-2(x+3)] = 7 {x-2[5-(2x+3)]
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23-2[4+3x-3]+5[x-2x-6] = 7 {x-2[5-2x-3]
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23-2[1+3x]+5[-x-6] = 7{x-2[2-2x]
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23-2-6x-5x-30 = 7{x-4+4x]
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-9-11x = 7{5x-4]
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-9-11x = 35x-28
46x = 19
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x = 19/46
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Cheers,
Stan H.
You can put this solution on YOUR website!
I hope I copied it OK. I slightly changed it to
make it more readable to me.
You're right. It looks like a jumble to me, too, and
I'm pretty good with these things. What you have to do
to make it less of a jumble is to not look at the whole thing
at once, (like not looking down if you're climbing up a cliff)
-----------------------------------------------------
(a) start by identifying the innermost brackets only.
then pick just one of them and try to simplify it.
I'll start with the (2x - 3) at the end, since it is nested
inside 3 sets of brackets like this: ((( ))).
It's got a (-) in front of it, so it becomes
I got rid of the innermost ().
(b) Now I'll move on to the next set of innermost ()s
which is the (x+3) in the middle inside 2 brackets:(())
It gets multiplied by the -2 in front, so
And I got rid of another set of ()s
Another innermost () is (x-3) moving left. It gets multiplied by
the 3 in front:
That's 3 sets of ()s I eliminated
(c) Now look for more innermost ()s.
The (5 - 2x - 3) is one. It gets multiplied by the -2 in front, so
(d) Now there are no more innermost ()s so just choose among
the brackets that are left. I'll just do them all in one step:
(e) Now just collect like terms:
This could be wrong, since it's so easy to make a mistake
along the way, but the idea is what's important. Start from
the inside ()s and work your way out.