SOLUTION: Evaluate the exponential values for three positive values of x, three negative values of x, and x = 0. Transform the second expression into the equivalent logarithmic equation; and

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Question 270430: Evaluate the exponential values for three positive values of x, three negative values of x, and x = 0. Transform the second expression into the equivalent logarithmic equation; and evaluate the equation for values of x that are greater than 1, between 0 and 1, and x = 1. Show work and plot graph.
y = (1/2)^x, x = (1/2)^y
This is what I have but I don't understand what they mean by transforming the second expression into the equivalent lagarithmic equation. Can you please help me?
y = 2^-x
x = 3 y = 2^-3 = .125
x = 2 y = 2^-2 = .25
x = 1 y = 2^-1 = .5
x = 0 y = 2^0 = 0
x = -1 y = 2^1 = 1
x = -2 y = 2^2 = 4

x = -3 y = 2^3 = 8

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Recall that x=b%5Ey can be rewritten as y=log%28b%2C%28x%29%29


So this means that can be rewritten as . Let me know if that helps.