SOLUTION: a concrete mix requires 2 parts sand and three parts cement. How manypds are need for 75 pounds of cement? ( guess an varable fraction problem)
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Question 270382: a concrete mix requires 2 parts sand and three parts cement. How manypds are need for 75 pounds of cement? ( guess an varable fraction problem) Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website! a concrete mix requires 2 parts sand and three parts cement. How manypds are need for 75 pounds of cement? ( guess an varable fraction problem)
The ratio of sand to cement in the concrete mixture is 2/3. Let x be the amount of sand needed to mix with 75 lbs of cement.
Then we know that:
2/3 = x/75
Multiply both sides of the equation above by 75:
(2/3)*75 = (x*75)/75
50 = x
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