SOLUTION: what is the probability that a king will be selected in the first and second draw (assuming the king was not replaced)? I thought it would be : (4/52)(3/51) but that equals 4.52

Algebra ->  Probability-and-statistics -> SOLUTION: what is the probability that a king will be selected in the first and second draw (assuming the king was not replaced)? I thought it would be : (4/52)(3/51) but that equals 4.52       Log On


   



Question 270351: what is the probability that a king will be selected in the first and second draw (assuming the king was not replaced)?
I thought it would be :
(4/52)(3/51) but that equals 4.52 and i know it cannot be greater than 1. What am i missing. The book states it should be .0045.
thanks

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
It is (4/52)*(3/51) = 1/13*17
=~ 0.0045