Question 270348: The sum of a two-digit number is 12. The number with the digits reversed is 15 times the original tens digit, Find the original number. Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website! The sum of a two-digit number is 12. The number with the digits reversed is 15 times the original tens digit, Find the original number.
Let x be the tens digit and y be the ones digit of the number. The number then is 10*x + 1*y. So the number with the digits reversed is 10*y + 1*x and we have:
1.) x + y = 12 and
2.) 10*y + 1*x = 15*x
Rewriting the above as:
3.) x = 12 - y
4.) 10y + x = 15x
Substituting 12-y for x from 3.) in 4.) gives:
10y + (12-y) = 15*(12-y)
Solve the above for y then calculate x = 12 - y.
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