SOLUTION: A cross-country flight traveling with the wind covers 3000 miles in 5 hours. The same plane then changes direction and travels to Texas, against the wind, covering 1500 miles in 3

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Question 270275: A cross-country flight traveling with the wind covers 3000 miles in 5 hours. The same plane then changes direction and travels to Texas, against the wind, covering 1500 miles in 3 hours. What are the wind speed, and the speed of the plane in still air?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let p = plane's speed in still air
Let w = wind speed
Flying with the wind:
d%5B1%5D+=+%28p+%2B+w%29%2At%5B1%5D
Flying against the wind:
d%5B2%5D+=+%28p+-+w%29%2At%5B2%5D
-------------------------
given:
(1) 3000+=+%28p+%2B+w%29%2A5
(2) 1500+=+%28p+-+w%29%2A3
-------------------------
(1) 5p+%2B+5w+=+3000
(2) 3p+-+3w+=+1500
multiply both sides of (1) by 3
and both sides of (2) by 5
Then add the equations
(1) 15p+%2B+15w+=+9000
(2) 15p+-+15w+=+7500
30p+=+16500
p+=+550 mi/hr
and, from (2)
(2) 3p+-+3w+=+1500
3%2A550+-+3w+=+1500
1650+-+3w+=+1500
3w+=+1650+-+1500
3w+=+150
w+=+50 mi/hr
the wind speed is 50 mi/hr
the plane's speed in still air is 550 mi/hr
check:
(1) 3000+=+%28p+%2B+w%29%2A5
3000+=+%28550+%2B+50%29%2A5
3000+=+600%2A5
3000+=+3000
(2) 1500+=+%28p+-+w%29%2A3
1500+=+%28550+-+50%29%2A3
1500+=+500%2A3
1500+=+1500
OK