SOLUTION: I have to use the FOIL to find the product. Express the product as descending powers of the variable.
(5x^3 -4) (x+5x^2)
This is what I have tried
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: I have to use the FOIL to find the product. Express the product as descending powers of the variable.
(5x^3 -4) (x+5x^2)
This is what I have tried
Log On
If I graph both equations, they should look like one equations since both forms are equivalent.
the graph of these equations looks like this:
That looks like one superimposed graph to me so I'll assume I did the arithmetic correctly.
What you did wrong was the following:
F(5x^3) (x)=5x^3
You got the F part right, but the arithmetic was off.
Answer should have been 5x^3*x = 5x^(3+1) = 5x^4.
O(5x^3) (5x^2)=10x^6
You got the O part right, but the arithmetic was off again.
Answer should have been 5x^3 * 5x^2 = 5*5*x^(3+2) = 25*x^5.
I (-4) (x)= -4x
Looks like you got this part right since -4*x does equal -4x.
L (-4) (5x^2 ) = -20x^2
Looks like you got this part right also since -4 * 5x^2 = -4*5*x^2 = -20x^2
10x^6 +5x^3 -20x^2 -4x
Your total is off because your piece parts were off.
Your piece parts were off because your arithmetic was off.
with exponents, x^a*x^b = x^(a+b)
with coefficients, ax * bx = a*x*b*x = (a*b)*(x*x)
your factors of 5x^2 * 5x^3 needed to become (5*x^2) * (5*x^3) which needed to become (5*5) * (x^2*x^3) which then needed to become 25 * x(2+3) which would finally become 25*x^5.
