Question 270162: Maria has $1-coins and 50-centavos coins. If she has 3,600 coins in all, and amounting to $2250, how many coins of each kind does she have?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Maria has $1-coins and 50-centavos coins. If she has 3,600 coins in all, and amounting to $2250, how many coins of each kind does she have?
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One-variable solution:
Equation:
value + value = value
100x + 50(3600-x) = 225000 centavos
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100x + 180000 - 50x = 225000
150x = 45000
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x = 300 (# of $1 coins)
3600-300 = 3300 (# of 50 centavos coins)
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Cheers,
Stan H.
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