SOLUTION: Find two consecutive odd intergers such that when the smaller is added to twice the larger the, the result is 24 more than the larger integer. The formula I used was this x+x+2=

Algebra ->  Linear-equations -> SOLUTION: Find two consecutive odd intergers such that when the smaller is added to twice the larger the, the result is 24 more than the larger integer. The formula I used was this x+x+2=      Log On


   

Question 27015: Find two consecutive odd intergers such that when the smaller is added to twice the larger the, the result is 24 more than the larger integer.
The formula I used was this x+x+2=24.
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Let the two consective odd integers be x and x+2
x+2(x+2)=24+(x+2)
x+2x+4=24+x+2
3x+4=26+x
2x=22
x=11

11+2=13

Hence, the two odd integers are 11 and 13.
Paul.