SOLUTION: I am not understanding how to add polynomials that are in fraction form. (-2)/(y^2-9) + (4y)/(y-3)^2 + (6)/(3-y) I have never used this before so I hope the way I entered it

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am not understanding how to add polynomials that are in fraction form. (-2)/(y^2-9) + (4y)/(y-3)^2 + (6)/(3-y) I have never used this before so I hope the way I entered it       Log On


   

Question 269957: I am not understanding how to add polynomials that are in fraction form.
(-2)/(y^2-9) + (4y)/(y-3)^2 + (6)/(3-y)
I have never used this before so I hope the way I entered it makes sense. I really struggle with regular polynomials so this really throws me for a loop. Your help is appreciated. Thank you!
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
polynomials that are in fraction form.
%28-2%29%2F%28y%5E2-9%29 + %284y%29%2F%28y-3%29%5E2 + %286%29%2F%283-y%29
:
Do some factoring, then determine a common denominator
%28-2%29%2F%28%28y-3%29%28y%2B3%29%29 + %284y%29%2F%28%28y-3%29%28y-3%29%29 + %286%29%2F%28-1%28y-3%29%29%29
that -1 with change the sign on the last fraction
%28-2%29%2F%28%28y-3%29%28y%2B3%29%29 + %284y%29%2F%28%28y-3%29%28y-3%29%29 - %286%29%2F%28%28y-3%29%29%29
the common denominator: (y-3)(y-3)(y+3)
:

:
%28-2y%2B6+%2B+4y%5E2%2B12y-6%28y%5E2-9%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29
:
%28%284y%5E2%2B10y-6y%5E2%2B6%2B54%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29 = %28%28-2y%5E2%2B10y%2B60%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29 = %28-2%28y%5E2-5y-30%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29 = -%282%28y%5E2-5y-30%29%29%2F%28%28y-3%29%28y-3%29%28y%2B3%29%29