SOLUTION: A train leaves Calgary traveling east at 30km/h. Two hours later another train leaves Calgary traveling in the same direction on a parallel track at 45km/h. At what point will the

Algebra ->  Length-and-distance -> SOLUTION: A train leaves Calgary traveling east at 30km/h. Two hours later another train leaves Calgary traveling in the same direction on a parallel track at 45km/h. At what point will the       Log On


   

Question 269944: A train leaves Calgary traveling east at 30km/h. Two hours later another train leaves Calgary traveling in the same direction on a parallel track at 45km/h. At what point will the faster train overtake the slower one?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
D1=30T
D2=45(T-2)
THE 2 DISTANCES ARE THE SAME THUS:
30T=45(T-2)
30T=45T-90
30T-45T=-90
-15T=-90
T=-90/-15
T=6 HOURS THEY WILL MEET.
PROOF:
30*6=45(6-2)
180=45*4
180=180