SOLUTION: What are three consecutive integers such that the sum of the first, twice the second, and three times the third is 80?

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Question 269883: What are three consecutive integers such that the sum of the first, twice the second, and three times the third is 80?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
x+%2B+2%2A%28x+%2B+1%29+%2B+3%2A%28x+%2B+2+%29+=+80
distributing, we get
x+%2B+2x+%2B+2+%2B+3x+%2B+6+=+80
combine like terms, we get
6x+%2B+8+=+80
subtract 8 to get
6x+=+72
divide to get
x+=+12
the 3 numbers are 12, 13, 14