SOLUTION: solve by quadratic equation. Find 3 positive consecutive integers such that the sum of their squares is 245

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Question 269817: solve by quadratic equation. Find 3 positive consecutive integers such that the sum of their squares is 245
Found 2 solutions by drk, Alan3354:
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+1 and x + 2 be 3 positive consecutive integers.
we get
(i) x%5E2+%2B+%28x%2B1%29%5E2%2B+%28x%2B2%29%5E2+=+245
expanding, we get
(ii) x%5E2++%2B+x%5E2+%2B+2x+%2B+1+%2B+x%5E2+%2B+4x+%2B+4+=+245
combine like terms to get
(iii) 3x%5E2+%2B+6x+%2B+5+=+245
set = 0 to get
(iv) 3x%5E2+%2B+6x+-+240+=+0
factoring, we get
(v) %28x%2B10%29%283x-24%29+=+0
and solving for x, we get
x = -10
or
x = 8.
The three numbers are 8, 9, and 10.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The short way:
245/3 = 81 +
Sqrt(81) = 9, the middle number