SOLUTION: Mrs. Johnson is 3 times as old as her son. Ten years ago she was 5 times as old as her son was then. Find each of their ages.

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Question 269775: Mrs. Johnson is 3 times as old as her son. Ten years ago she was 5 times as old as her son was then. Find each of their ages.
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Set Up:
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Let Mrs. Johson's age = A
Let the son's age = B
Equation 1: A+=+3B (She is tree times as old as here son)
Equation 2: A+-+10+=+5%2A%28B+-+10%29 (She was 5 times as old 10 years ago)
Solution:
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We can substitute 3B into equation 2 for A
Equation 2: A+-+10+=+5%2A%28B+-+10%29
%283B%29+-+10+=+5%2A%28B+-+10%29 Simplify
3B+-+10+=+5B+-+50 Subtract 3B from both sides
-10+=+5B+-+50+-+3B Add 50 to both sides
50+-+10+=+5B+-+3B Simplify
40+=+2B Divide both sides by 2
highlight%2820+=+b%29
Now we can plug 20 into equation 1 for B
Equation 1: A+=+3B
A+=+3%2A%2820%29
highlight%28A+=+60%29
Check you Answers
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Plug you values back into both equations to check them
Equation 1: A+=+3B
60+=+3%2A%2820%29
highlight%2860+=+60%29
Equation 2: A+-+10+=+5%2A%28B+-+10%29
60+-+10+=+5%2A%2820+-+10%29
highlight%2850+=+50%29