SOLUTION: how much of an alloy that is 10% copper should be mixed with 500 ounces of an alloy that is 70% copper in order to get an alloy that is 20% copper?

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Question 269725: how much of an alloy that is 10% copper should be mixed with 500 ounces of an alloy that is 70% copper in order to get an alloy that is 20% copper?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In words:
(ounces of copper in final mixture)/(ounces of final mixture)= 20%
Let x = ounces of 10% copper alloy needed
%28.1x+%2B+.7%2A500%29%2F%28x+%2B+500%29+=+.2
.1x+%2B+350+=+.2%2A%28x+%2B+500%29
.1x+%2B+350+=+.2x+%2B+100
.1x+=+250
x+=+2500
2500 ounces of 10% copper alloy are needed
check:
%28.1x+%2B+.7%2A500%29%2F%28x+%2B+500%29+=+.2
%28.1%2A2500+%2B+.7%2A500%29%2F%282500+%2B+500%29+=+.2
%28250+%2B+350%29%2F%282500+%2B+500%29+=+.2
600%2F3000+=+.2
600+=+600
OK