SOLUTION: A man's boyhood lasted 1/6 of his life,he played football for the next 1/8 of his life and married five years after quitting football. a daughter was born after he had been married

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Question 269710: A man's boyhood lasted 1/6 of his life,he played football for the next 1/8 of his life and married five years after quitting football. a daughter was born after he had been married 1/12 of his life. the daughter lived 1/2 as many years as her father. the man died 6 years after his daughter. use a number line. then write an equation and solve
Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let = number of years the man was alive
boyhood =
years played football =
years between football and marriage =
years after marriage daughter was born =
years Daughter was alive =
years after daughter died that man died =
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All of this added together is the man's whole lifetime, so

Multiply both sides of equation by

The man lived to be 88 years old
check:

OK