SOLUTION: Bob has some money invested at 5%, and $5,000 more than this amount invested at 9%. His annual interest income is $1430. What is the amount invested at each rate.

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Question 269447: Bob has some money invested at 5%, and $5,000 more than this amount invested at 9%. His annual interest income is $1430. What is the amount invested at each rate.
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Let Bob have x dollars to invest. we want the equation
I = prt + prt
for two investments.
From above we get
(i) 1430+=+x%28.05%29%281%29+%2B+%28x%2B5000%29%2A%28.09%29%281%29
step 1 - multiply and simplify the right side to get
(ii) +1430+=+.05x+%2B+.09x+%2B+450
and then
(iii) 1430+=+.14x+%2B+450
step 2 - subtract 450 to get
(iv) 980+=+.14x
step 3 - divide by .14 to get
(v) x+=+7000
and then x+%2B+5000+=+12000
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7000 @ 5%
12000 @ 9%