SOLUTION: evaluate the logarithmic equation for three values of x that are greater than -1, three values of x that are between -2 and -1, and at x = -1. Show your work.
y = 1n(x + 2). I do
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y = 1n(x + 2). I do
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Question 269407: evaluate the logarithmic equation for three values of x that are greater than -1, three values of x that are between -2 and -1, and at x = -1. Show your work.
y = 1n(x + 2). I don't know where to begin and have been trying to figure it out since Thursday. Answer by jsmallt9(3758) (Show Source):
You can put this solution on YOUR website! All you need is a calculator that "knows" natural logarithms (ln). And if your calculator can handle parentheses it is very easy.
You are asked to evaluate the logarithm for 7 values of x (-1, 3 greater than -1 and 3 between -1 and -2). For each of these values of x you find ln(x+2). The result you get from your calculator will be the y value that goes with that x.
I'll do one for you. Let's try x = 0 (one of the 3 numbers greater than -1).
y = ln((0)+2)
y = ln(2)
Here is where we use our calculator to find ln(2):
y = 0.6931471805599453
Just repeat this for the other 6 values and you will end up with 7 ordered pairs (which you could use to graph the equation if you were asaked to graph it).
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