use the equation y=mx+b where m=slope and b=y-intercept
slope = y-axis/x-axis
im not going to show the graph since your asking how to graph
starting at point (0,1) and with the given slope(-5/4) the easiest way to find the otherpoints is to use this plot system where a/b=slope
(x+b,y+a)
(x+(4),y+(-5))
(0+(4),1+(-5))
(4,-4)
(x+b,y+a) repeat with the previous point
(x+(4),y+(-5))
(4+(4),-4+(-5))
(8,-9)
now you have 3 points to draw a line
OR
if you cant remember how to use the slope to make your points then you will have to find points to make your line.
easiest way to draw the line is to make a chart of x-coordinates that will give u easy y-coordinates to graph. normally i would do {x=0,1} but since we are dealing with a fraction for the slope, i would want to use numbers that would cross cancel and leave whole numbers. I would use {x=4,-4}. i will use these numbers as they are easily divisiable by 4 which is the denominator of the slope. so lets find our y-cordinates:
and 
we get these two pairs: and we know the line crosses y-axis at +1.
(4,-4)
(-4,6)
plot the points and draw your line
(-4,6),(0,1),(4,-4)
should look like a "\" line
