SOLUTION: A large watermelon weighs 20 kg with 98% of its weight being water. It is left to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. Wha

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Question 269355: A large watermelon weighs 20 kg with 98% of its weight being water. It is left to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. What is its reduced weight?
(A)17 kg (B) 19.4 kg (C) 10 kg (D) 8 kg (E) None of these.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A large watermelon weighs 20 kg with 98% of its weight being water. It is left to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. What is its reduced weight?
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amt of water before drying: 0.98*20 = 19.6 kg
non-water weight of the melon: 0.4 kg
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After drying:
Let weight be "x".
Equation:
The non-water material in the melon is now 5% of its weight.
0.05x = 0.4 kg
x = 8 kg
The melon now weighs 8 kg.
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Cheers,
Stan H.





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(A)17 kg (B) 19.4 kg (C) 10 kg (D) 8 kg (E) None of these.