SOLUTION: Gerry mixes different solutions with concentrations of 25%, 40%, and 50% to get 200 liters fo a 32% solution. Also, it takes twice the liters of the 40% solution to equal the same

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Question 269223: Gerry mixes different solutions with concentrations of 25%, 40%, and 50% to get 200 liters fo a 32% solution. Also, it takes twice the liters of the 40% solution to equal the same liters of the 25% , find how mnay liters of each kind he uses.
I have set up a table, but do not understand how the 50% factors in. Please help. Thank you!
Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let = liters of 25% solution needed
Let = liters of 40% solution needed
Let = liters of 50% solution needed
given:
(1) liters
(2) liters

(3)
Multiply both sides of (1) by
and subtract from (3)
(3)
(1)

Going back to (1)
(1)

And, since

(1)

120 liters of 25% solution are needed
60 liters of 40% solution are needed
20 liters of 50% solution are needed
check:

OK