SOLUTION: A 4-inch by 6-inch picture is enlarged for framing by tripling its dimensions. A 2-inch-wide border is then placed around each side of the enlarged picture, as shown. Thin metal fr

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: A 4-inch by 6-inch picture is enlarged for framing by tripling its dimensions. A 2-inch-wide border is then placed around each side of the enlarged picture, as shown. Thin metal fr      Log On

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Question 269130: A 4-inch by 6-inch picture is enlarged for framing by tripling its dimensions. A 2-inch-wide border is then placed around each side of the enlarged picture, as shown. Thin metal framing is sold only in increments of one foot. What is the minimum number of linear feet of framing that must be purchased to go around the perimeter of the border?
Answer by mananth(16946) About Me  (Show Source):
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A 4-inch by 6-inch picture is enlarged for framing by tripling its dimensions. A 2-inch-wide border is then placed around each side of the enlarged picture, as shown. Thin metal framing is sold only in increments of one foot. What is the minimum number of linear feet of framing that must be purchased to go around the perimeter of the border?
width 4 inch tripled so width = 12
length 6 inch tripled = 18
border width 2inch
total length = 18+4= 22 inch
total width = 12 +4 =16 inch
perimeter = 2L + 2W
2*22+2*16
44+32= 76
so 7 running feet will be required.