SOLUTION: Need some help with these problems: 1. Simplify by taking roots of the numerator and the denominator 3{{{ sqrt( 729x^8/y3 ) }}} I dont know if I did it right but the probl

Algebra ->  Square-cubic-other-roots -> SOLUTION: Need some help with these problems: 1. Simplify by taking roots of the numerator and the denominator 3{{{ sqrt( 729x^8/y3 ) }}} I dont know if I did it right but the probl      Log On


   

Question 268985: Need some help with these problems:
1. Simplify by taking roots of the numerator and the denominator
3+sqrt%28+729x%5E8%2Fy3+%29+
I dont know if I did it right but the problem is a radical with a degree of 3.
thanks


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
root%283%2C%28729x%5E8%29%2F%28y%5E3%29%29 Start with the given expression.


root%283%2C729x%5E8%29%2Froot%283%2Cy%5E3%29 Break up the root.


root%283%2C9%5E3x%5E8%29%2Froot%283%2Cy%5E3%29 Rewrite 729 as 9%5E3


root%283%2C9%5E3x%5E3%2Ax%5E3%2Ax%5E2%29%2Froot%283%2Cy%5E3%29 Factor x%5E8 to get x%5E3%2Ax%5E3%2Ax%5E2


Break up the root in the numerator.


%289x%2Ax%2Aroot%283%2Cx%5E2%29%29%2Fy Evaluate the cube roots of 9%5E3, x%5E3 and y%5E3 to get 9, 'x', and 'y'.


%289x%5E2%2Aroot%283%2Cx%5E2%29%29%2Fy Multiply


So root%283%2C%28729x%5E8%29%2F%28y%5E3%29%29=%289x%5E2%2Aroot%283%2Cx%5E2%29%29%2Fy where y%3C%3E0