SOLUTION: bOB HAS 60 COINS CONSISTING OF QUARTERS AND DIMES.tHE COINS COMBINED VALUE IS $9.45. FIND OUT HOW ARE QUATERS AND MANY DIMES.

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: bOB HAS 60 COINS CONSISTING OF QUARTERS AND DIMES.tHE COINS COMBINED VALUE IS $9.45. FIND OUT HOW ARE QUATERS AND MANY DIMES.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 268974: bOB HAS 60 COINS CONSISTING OF QUARTERS AND DIMES.tHE COINS COMBINED VALUE IS $9.45. FIND OUT HOW ARE QUATERS AND MANY DIMES.
Found 2 solutions by drk, JBarnum:
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
we need two equations
(i) D+%2B+Q+=+60
(ii) 10D+%2B+25Q+=+945
step 1 - multiply (i) by -10 to get
(iii) -10D+-+10Q+=+-600
step 2 - add (ii) and (iii) to get
(iv) 15Q+=+345
step 3 - divide by 15 to get
(v) Q+=+23
Since Q =23, we know that
(vi) +D+=+37

Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
Q%2BD=60 where 60=total coins and D is the number of dimes and Q is the number of quarters. the value of C=9.45 so the value of Q+ the value of D= the value of C. to make this a bit easier to see the value of quarters =Q(.25) , the value of dimes =D(.10) , and the value of the total coins =9.45
this equation looks like: Q%28.25%29%2BD%28.10%29=9.45
now you have 2 equations and now u can use the substitution method to find your answers.
_______________
Equations:
Q%28.25%29%2BD%28.10%29=9.45
Q%2BD=60 so D=60-Q
_____________________
Q%28.25%29%2B%2860-Q%29%28.10%29=9.45
.25Q%2B6-.10Q=9.45
.25Q%2B6-6-.10Q=9.45-6
.25Q-.10Q=3.45
.15Q%2F.15=3.45%2F.15
Q=23 23 Quarters
____________________
D=60-Q
D=60-23
D=37 37 Dimes
_____________________
Check answer
Q%28.25%29%2BD%28.10%29=9.45
23%28.25%29%2B37%28.10%29=9.45
5.75%2B3.70=9.45
9.45=9.45
correct