SOLUTION: the product of 2 consecutive positive integers in 71 more than their sum. Find the integers.

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Question 268576: the product of 2 consecutive positive integers in 71 more than their sum. Find the integers.

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x & (x+1) be the 2 integers.
x(x+1)=x+x+1+71
x^2+x=2x+72
x^2+x-2x-72=0
(x^2-x-72=0
(x-9)(x+8)=0
x-9=0
x=9 ans.
9+1=10 ans.
9*10=9+10+71
90=90