Question 268567: A speeding car has the equation d2=-2t^2+d1, where d2 is the distance from the concrete barrier at the time (t) and d1 is the original distance of the speeding car from the concrete barrier. If the speeding car is 50 yards from the concrete barrier originally, how many seconds before it hits the concrete barrier? When the car hits the concrete barrier, the distance (d2) is 0.
Thank you in advance for your help.
Tina
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A speeding car has the equation d2=-2t^2+d1, where d2 is the distance from the concrete barrier at the time (t) and d1 is the original distance of the speeding car from the concrete barrier.
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If the speeding car is 50 yards from the concrete barrier originally, how many seconds before it hits the concrete barrier? When the car hits the concrete barrier, the distance (d2) is 0.
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-2t^2 + 50 = 0
-2t^2 = -50
t^2 = 25
Positive solution:
t = 5 seconds
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Cheers,
Stan H.
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