SOLUTION: The sum of 3 times a number and 4 times another number is 43. Five times the first number is 3 less than four times the opposite of the second number. Find the numbers.

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Question 268447: The sum of 3 times a number and 4 times another number is 43. Five times the first number is 3 less than four times the opposite of the second number. Find the numbers.
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of 3 times a number and 4 times another number is 43
translates to
(i) 3x+%2B+4y+=+43
Five times the first number is 3 less than four times the opposite of the second number
translates to
(ii) 5x+=+4%28-y%29+-+3
step 1 - rewrite (ii) so that x and y are on the same side to get
(iii) 5x+%2B+4y+=+-3
step 2 - multiply (iii) by -1 to get
(iv) -5x+-+4y+=+3
step 3 - add (i) and (iv) to get
(v) -2x+=+46
step 4 - divide to get
(vi) +x+=+-23
Step 5 - solve for y to get
y+=+28