SOLUTION: i need help finding x in the equation: 2(squareroot x) + 3 = x

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Question 268365: i need help finding x in the equation: 2(squareroot x) + 3 = x
Found 5 solutions by mananth, ikleyn, timofer, josgarithmetic, MathTherapy:
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
i need help finding x in the equation: 2(squareroot x) + 3 = x
2sqrtx +3=x
2sqrtx=x-3
square both the sides of the equation
4x=(x-3)^2
4x=x^2-6x+9
x^2-4x-6x-9=0
x^2-10x-9=0
x^2-9x-x+9=0
x(x-9)-1(x-9)=0
(x-1)(x-9)=0

Answer by ikleyn(53742) About Me  (Show Source):
You can put this solution on YOUR website!
.
i need help finding x in the equation: 2(squareroot x) + 3 = x
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        In the post by @mananth, the solution is incomplete and is written inaccurately;
        the answer absents, and from his post, a reader can make wrong conclusion.

        So, I came to present an accurate and complete solution.


2sqrtx +3=x
2sqrtx=x-3
square both the sides of the equation
4x=(x-3)^2
4x=x^2-6x+9
x^2-4x-6x+9=0
x^2-10x+9=0
x^2-9x-x+9=0
x(x-9)-1(x-9)=0
(x-1)(x-9)=0

The roots to the last equation are x= 1 and x= 9.

The check shows that x= 9 satisfies the original equation,
while x= 1 is an extraneous solution and should be rejected.

ANSWER. The given equation has a unique solution x = 9.

Solved completely and accurately (as it should be done).



Answer by timofer(155) About Me  (Show Source):
Answer by josgarithmetic(39790) About Me  (Show Source):
You can put this solution on YOUR website!
2%2Asqrt%28x%29%2B3=x

2%2Asqrt%28x%29=x-3
4x=x%5E2-6x%2B9
x%5E2-10x%2B9=0
discriminant 100-4%2A9=100-36=64
x=10%2B-+sqrt%2864%29%29%2F2
x=%2810%2B-+8%29%2F2
x=5%2B-+4
x=1 or x=9 -------------check if either or both work

Answer by MathTherapy(10801) About Me  (Show Source):
You can put this solution on YOUR website!
i need help finding x in the equation: 2(squareroot x) + 3 = x
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The answer to this problem by one of the "respondents," timofer(153) AKA josgarithmetic(39765) is WRONG! See correct answer by @IKLEYN.

All other answers are BOGUS/FAKES, and should be REJECTED/IGNORED!

His answer: "(x=5%2B-+sqrt%2834%29-------------check if either or both will work...." 
BEWARE! You'll be checking from now to eternity and NEITHER would ever work!!