SOLUTION: find the area of the convex polygon in the plane with vertices at the points whose coordinates are (-2,3), (1,10), (5,10) (8,7), and (4,0).

Algebra ->  Polygons -> SOLUTION: find the area of the convex polygon in the plane with vertices at the points whose coordinates are (-2,3), (1,10), (5,10) (8,7), and (4,0).      Log On


   



Question 268147: find the area of the convex polygon in the plane with vertices at the points whose coordinates are (-2,3), (1,10), (5,10) (8,7), and (4,0).
Answer by Edwin McCravy(20085) About Me  (Show Source):
You can put this solution on YOUR website!

Graph the points:



Get them in order going counter-clockwise around
the polygon.  

(-2,3), (4,0), (8,7) (5,10), and (1,10).

Now we write the equation for the area in terms
of the 6x2 "determinant" where each ordered pair of 
coordinates appear on each row in that counter-
clockwise order, repeating the first ordered pair 
of coordinates at the bottom.



Now to evaluate that "determinant" we 

Add the sum of the products of each x-coordinate 
by the y-coordinate of the point just below it,
and then subtract the sum of the products of each 
y-coordinate by the x-coordinate of the point just 
below it.

So we get

 

A=%281%2F2%29%280%2B28%2B80%2B50%2B3%29-%2812%2B0%2B35%2B10-20%29

A=%281%2F2%29%28161-37%29

A=%281%2F2%29%28124%29

A=62

Edwin