SOLUTION: Solve for x, in interval notation: x^2-3/x-3 > or = 1/x-3. I came up with [-2,2]U[3,infinity). The quiz said it should be [-2,2]U(3,infinity). I think the book is wrong. If not, w
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-> SOLUTION: Solve for x, in interval notation: x^2-3/x-3 > or = 1/x-3. I came up with [-2,2]U[3,infinity). The quiz said it should be [-2,2]U(3,infinity). I think the book is wrong. If not, w
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Question 268087: Solve for x, in interval notation: x^2-3/x-3 > or = 1/x-3. I came up with [-2,2]U[3,infinity). The quiz said it should be [-2,2]U(3,infinity). I think the book is wrong. If not, why wouldn't 3 be the = part? Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Simple reason: you CANNOT divide by zero. If , then the denominator which is a violation of this rule. So that's why 3 was excluded from the solution set.
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