SOLUTION: x^2+3x-4=0 find real number solutions

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Question 268078: x^2+3x-4=0 find real number solutions
Answer by CharlesG2(834) About Me  (Show Source):
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x^2+3x-4=0 find real number solutions
(x+4)(x-1)=0 (foil: x^2 - x + 4x - 4 = 0)
x = -4 OR x = 1