SOLUTION: Here is a confusing question for me: The ratio of Aldo's cycling speed to Jose's cycling speed is 6:5. Jose leaves school at 3 P.M. and Aldo leaves at 3:10 P.M. By 3:30, Aldo is
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Question 267422: Here is a confusing question for me: The ratio of Aldo's cycling speed to Jose's cycling speed is 6:5. Jose leaves school at 3 P.M. and Aldo leaves at 3:10 P.M. By 3:30, Aldo is only 2 km behind Jose. How fast is each cycling? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The ratio of Aldo's cycling speed to Jose's cycling speed is 6:5.
Let m = the multiplier
then
6m = A's speed
and
5m = J's speed
:
Jose leaves school at 3 P.M. and Aldo leaves at 3:10 P.M. By 3:30,
J's travel time 30 min; hr
A's travel time 20 min; hr
:
By 3:30, Aldo is only 2 km behind Jose. How fast is each cycling?
;
Write a distance equation. Dist = time * speed
J's dist - A's dist = 2 km (5m) - (6m) = 2
Multiply by 6 to get rid of the denominators, results
3(5m) - 2(6m) = 6(2)
15m - 12m = 12
3m = 12
m = 4 is the multiplier
then
4(6) = 24 km/hr is A's speed
and
4(5) = 20 km/hr is J's speed
:
:
Check solution by finding the dist traveled by each
J: .5(20) = 10 km
A: .33(24)= 8 km
---------------------
difference = 2 km
