SOLUTION: Find the vertex. Is the vertex a maximum or minimum point? Graph the parabola. a(x) = x^2 -4x +4

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex. Is the vertex a maximum or minimum point? Graph the parabola. a(x) = x^2 -4x +4      Log On


   



Question 267384: Find the vertex. Is the vertex a maximum or minimum point? Graph the parabola.
a(x) = x^2 -4x +4

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Factoring the original equation, we get
(x-2)*(x-2)
However, that can be expressed as
(x-2)^2
SInce there is no number after the squared binomial, the vertex form of this is
y = (x-2)^2 + 0
The vertex is "opposite of the inside number, outside number"
so the vertex is (2,0)
The vertex shows us a minimum
Here is the graph
+graph%28+300%2C+200%2C+-5%2C+5%2C+-10%2C+10%2C+%28x-2%29%5E2%29+