SOLUTION: Find two consecutive integers whose product is 6 less than the square of the larger number.

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Question 267375: Find two consecutive integers whose product is 6 less than the square of the larger number.
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%29%28x%2B1%29+=+%28x%2B1%29%5E2+-+6
step 1 -expand both sides to get
x%5E2+%2B+x+=+x%5E2+%2B+2x+%2B+1+-+6
step 2 - combine like terms on the right to get
x%5E2+%2B+x+=+x%5E2+%2B+2x+-+5
step 3 - set = 0 as
0+=+x-5
step 4 - solve for x to get
x+=+5
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we get
x = 5
x + 1 = 6