SOLUTION: determine whether the given systems are solvable 1. x+2y+3z =1 -x+y =-2 2x-3x+z =0 2. x+2y+3z =-1 4x+5y+6z =0 7x+8y+9z =1

Algebra ->  Matrices-and-determiminant -> SOLUTION: determine whether the given systems are solvable 1. x+2y+3z =1 -x+y =-2 2x-3x+z =0 2. x+2y+3z =-1 4x+5y+6z =0 7x+8y+9z =1      Log On


   

Question 267121: determine whether the given systems are solvable
1. x+2y+3z =1
-x+y =-2
2x-3x+z =0
2. x+2y+3z =-1
4x+5y+6z =0
7x+8y+9z =1
Found 2 solutions by richwmiller, drk:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
first yes second no

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
(1) is solvable
(2) not solvable - line 2 and three will cancel each other out