Question 267038: A bullet is shot into the air at an initial rate of 900 feet per second from a height of 9 feet. How high does the bullet travel? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Using 32/ft/sec/sec as Earth's gravity:
h(t) = -16t^2 + 900t + 9 (t in seconds, h in feet)
The function is a parabola, the vertex is the max height
Vertex at t = -b/2a = -900/-32 = 225/8 seconds
h(225/8) = 12665.25 feet