SOLUTION: A couple has a 2/3 probability of passing on brown eyes to their children. If they have four children, what is the probability that none of the children will have brown eyes? A

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Question 266871: A couple has a 2/3 probability of passing on brown eyes to their children. If they have four children, what is the probability that none of the children will have brown eyes?
A) 1/81

B) 8/27

C) 16/81

D) 1/27


Thank you :)

Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
A couple has a 2/3 probability of passing on brown eyes to their children. If they have four children, what is the probability that none of the children will have brown eyes?
Since the probablility of brown eyes is 2/3 the probability of not brown eyes is 1 - 2/3 = 1/3.
The probability of brown eyes four times is:
(1/3)*(1/3)*(1/3)*(1/3) = 1/3^4 = 1/81