SOLUTION: A couple has a 2/3 probability of passing on brown eyes to their children. If they have four children, what is the probability that none of the children will have brown eyes?
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Question 266776: A couple has a 2/3 probability of passing on brown eyes to their children. If they have four children, what is the probability that none of the children will have brown eyes?
Thank you :) Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! We have 4 children, 0 of them should have brown eyes.
P(brown) = 2/3
P(not brown) = 1/3
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P(none brown) = (4c0)*(2/3)^0*(1/3)^4 ~ 0.012345679
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