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Question 266656: find three consecutive even integers such that the product of the first and third is 24 less than 9 times the second
Answer by unlockmath(1688)   (Show Source):
You can put this solution on YOUR website! Hello,
Let's have x be the first even integer and x+2 be the next and x+4 be the next. OK, now we can set up an equation like this:
x(x+4)=9(x+2)-24 Rewritten it looks like:
x^2+4x=9x+18-24 Rewritten as:
x^2+4x=9x-6 Subtract 9x and add 6 to both sides to get:
x^2-5x+6=0 Factor this out to be:
(x-3)(x-2)=0 Solve x:
x=3 This obviously doesn't work since it not an even integer so the answer is:
x=2 From here you know the next two even integers.
RJ
Check out a book I wrote at:
www.math-unlock.com
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