SOLUTION: In a parallelogram, if you have two base numbers such as 67ft and 60 ft and a height number such as 52ft, how do you find the area? Jeremy H

Algebra ->  Parallelograms -> SOLUTION: In a parallelogram, if you have two base numbers such as 67ft and 60 ft and a height number such as 52ft, how do you find the area? Jeremy H      Log On


   

Question 266552: In a parallelogram, if you have two base numbers such as 67ft and 60 ft and a height number such as 52ft, how do you find the area? Jeremy H
Found 2 solutions by stanbon, drk:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In a parallelogram, if you have two base numbers such as 67ft and 60 ft and a height number such as 52ft, how do you find the area?
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Area = (1/2)h(b1 + b2)
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A = (1/2)(52)(67+60)
A = 26(127)
A = 3302 sq. ft.
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Cheers,
Stan H.

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a parallelogram is
A = bh
Now the h should be perpendicular to one of the bases. I don't know if 52 is perpendicular to the 67 or the 60. Here are the two options:
(1) 52*67 = 3484 sq. ft.
(2) 52*60 = 3120 sq. ft.