SOLUTION: Find the foci of the ellipse whose equation is (y^2/16) + (x^2/12) = 1

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Question 26655: Find the foci of the ellipse whose equation is (y^2/16) + (x^2/12) = 1
Answer by venugopalramana(3286) About Me  (Show Source):
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Find the foci of the ellipse whose equation is (y^2/16)+(x^2/12)=1.
> COMPARING WITH STANDARD EQN. OF ELLIPSE
> (X^2/A^2)+(Y^2/B^2)+1...WE GET
> FOCI=(AE,0) AND (-AE,0)..WHERE E=SQRT.{(A^2-B^2)/A^2}
> WE HAVE A=4 AND E=SQRT.{(16-12)/16}=1/2..SO FOCI ARE..(2,0),(-2,0)