SOLUTION: factor completely t^3-8

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Question 266488: factor completely
t^3-8
Answer by vksarvepalli(154) About Me  (Show Source):
You can put this solution on YOUR website!
t^3-8
=> t%5E3-2%5E3
it is of the form a^3-b^3
we have (a^3-b^3)=(a-b)(a^2+ab+b^2)
similarly
(t^3-2^3)=(t-2)(t^2+2t+4)
so t^3-8 = (t-2)(t^2+2t+4)